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Never layout a child larger than the parent

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This commit is contained in:
Alexandre Bury 2017-11-06 17:11:09 -08:00
parent 3fc06ef048
commit 11ea8a592b
1 changed files with 19 additions and 6 deletions
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25
src/views/linear_layout.rs
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@ -21,6 +21,8 @@ pub struct LinearLayout {
struct Child {
view: Box<View>,
// The last result from the child's required_size
// Doesn't have to be what the child actually gets.
size: Vec2,
weight: usize,
}
@ -242,6 +244,9 @@ impl View for LinearLayout {
// Use pre-computed sizes
let mut offset = Vec2::zero();
for (i, child) in self.children.iter().enumerate() {
// eprintln!("Printer size: {:?}", printer.size);
// eprintln!("Child size: {:?}", child.size);
// eprintln!("Offset: {:?}", offset);
let printer =
&printer.sub_printer(offset, child.size, i == self.focus);
child.view.draw(printer);
@ -263,6 +268,7 @@ impl View for LinearLayout {
fn layout(&mut self, size: Vec2) {
// If we can get away without breaking a sweat, you can bet we will.
// eprintln!("Laying out with {:?}", size);
if self.get_cache(size).is_none() {
self.required_size(size);
}
@ -272,7 +278,7 @@ impl View for LinearLayout {
for child in &mut self.children {
// Every item has the same size orthogonal to the layout
child.size.set_axis_from(o.swap(), &size);
child.view.layout(size.with_axis_from(o, &child.size));
child.view.layout(Vec2::min(size, child.size));
}
}
@ -283,12 +289,12 @@ impl View for LinearLayout {
}
// First, make a naive scenario: everything will work fine.
let sizes: Vec<Vec2> = self.children
let ideal_sizes: Vec<Vec2> = self.children
.iter_mut()
.map(|c| c.required_size(req))
.collect();
debug!("Ideal sizes: {:?}", sizes);
let ideal = self.orientation.stack(sizes.iter());
debug!("Ideal sizes: {:?}", ideal_sizes);
let ideal = self.orientation.stack(ideal_sizes.iter());
debug!("Ideal result: {:?}", ideal);
@ -301,10 +307,12 @@ impl View for LinearLayout {
// Ok, so maybe it didn't. Budget cuts, everyone.
// Let's pretend we have almost no space in this direction.
// budget_req is the dummy requirements, in an extreme budget situation.
let budget_req = req.with_axis(self.orientation, 1);
debug!("Budget req: {:?}", budget_req);
// See how they like it that way
// See how they like it that way.
// This is, hopefully, the absolute minimum these views will accept.
let min_sizes: Vec<Vec2> = self.children
.iter_mut()
.map(|c| c.required_size(budget_req))
@ -332,6 +340,9 @@ impl View for LinearLayout {
return desperate;
}
// So now that we know we _can_ make it all fit, we can redistribute
// the extra space we have.
// This here is how much we're generously offered
// (We just checked that req >= desperate, so the subtraction is safe
let mut available = self.orientation.get(&(req - desperate));
@ -339,7 +350,9 @@ impl View for LinearLayout {
// Here, we have to make a compromise between the ideal
// and the desperate solutions.
let mut overweight: Vec<(usize, usize)> = sizes
// This is the vector of (ideal - minimum) sizes for each view.
// (which is how much they would like to grow)
let mut overweight: Vec<(usize, usize)> = ideal_sizes
.iter()
.map(|v| self.orientation.get(v))
.zip(min_sizes.iter().map(|v| self.orientation.get(v)))