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Remove useless type assumption examples
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@ -16,15 +16,15 @@ root.exampleTerms=\
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let f = λx. let g = λy. y in g x in f 3,\
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let f = λx. let g = λy.5 5 in g x in f 3
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root.λx.x=∅;x: int;y: bool
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root.λx.λy.yx=∅;x: int;y: bool
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root.λx.λy.y(xx)=∅;x: int;y: bool
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root.λx.x=∅
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root.λx.λy.yx=∅
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root.λx.λy.y(xx)=∅
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root.letfλx.gyyinf3=∅;g: a->b->a;g: int->int->bool;g: int->int->bool, y: bool;g: int->int->bool, y: τ₁
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root.letkλx.λy.xinka(kbc)=∅;a: τ₁;a: ∀τ₁.τ₁->int, b: a;a: int, b: bool, c: char
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root.(λx.xx)(λx.xx)=∅;x: bool
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root.(λx.xx)(λx.xx)=∅
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root.(λx.λy.y(xy))(λz.λa.zga)=∅;g: bool;a: int, g: bool->int;g: ∀τ₂.τ₁->τ₂
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root.letfλx.letgλy.yingxinf3=∅;g: bool->int->bool
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root.letfλx.letgλy.55ingxinf3=∅;f: bool->int->bool
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root.letfλx.letgλy.55ingxinf3=∅
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root.termGrammar=\u2329Term\u232A ::= (\u2329Term\u232A) | \u2329App\u232A | \u2329Abs\u232A | \
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\u2329Let\u232A | \u2329Var\u232A | \u2329Const\u232A <br> \
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